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WGU Data Management – Foundations Exam Sample Questions (Q44-Q49):

NEW QUESTION # 44
Which database operation locates the needed table blocks?

  • A. Fan-out
  • B. Binary search
  • C. Table scan
  • D. Index scan

Answer: D

Explanation:
Anindex scanis a database operation thatquickly locates table blocksusing anindexrather than scanning the entire table. It significantly improves query performance.
Example Usage:
sql
SELECT * FROM Employees WHERE EmployeeID = 105;
* If EmployeeID isindexed, the database uses anindex scantoquickly find the record.
Why Other Options Are Incorrect:
* Option A (Binary search) (Incorrect):A searching algorithm, but not a database operation.
* Option B (Table scan) (Incorrect):Scans theentire table, which isslowerthan an index scan.
* Option C (Fan-out) (Incorrect):Refers tobranching in B-Treesbut doesnot locate table blocks directly.
Thus, the correct answer isIndex scan, as it efficiently locates table blocks.


NEW QUESTION # 45
Which phase of entity-relationship modeling refers to the maxima and minima of relationships and attributes?

  • A. Attribute minimum
  • B. Physical design
  • C. Partition
  • D. Cardinality

Answer: D

Explanation:
Cardinalitydefines theminimum and maximum number of occurrencesof one entity in relation to another.
Example Usage in an ER Model:
* One-to-Many (1:M): Acustomer can place multiple orders, but each order belongs to onlyone customer.
Customers (1) --- (M) Orders
* Cardinality notation:
(1,1) # One-to-One
(0,M) # Zero-to-Many
(1,M) # One-to-Many
Why Other Options Are Incorrect:
* Option B (Physical design) (Incorrect):Focuses onstorage and indexing, not relationships.
* Option C (Attribute minimum) (Incorrect):No such formal term in database modeling.
* Option D (Partition) (Incorrect):Refers todividing tables, not relationship constraints.
Thus, the correct answer isCardinality, as it definesmin/max constraints on relationships.


NEW QUESTION # 46
Which relationship or association exists between a supertype and its subtype entities?

  • A. IsA relationship
  • B. Associative entity
  • C. Strong entity
  • D. Weak entity

Answer: A

Explanation:
Indatabase modeling, the relationship between asupertype and its subtypesis called anIsA relationship.
Example Usage:
* AVehicle supertypemay haveCar and Truck subtypes.
Vehicle
### Car
### Truck
* InER diagrams, this is represented as:
Vehicle (Supertype)
|
### Car (Subtype)
### Truck (Subtype)
* SQL Table Implementation:
sql
CREATE TABLE Vehicle (
VehicleID INT PRIMARY KEY,
Make VARCHAR(50),
Model VARCHAR(50)
);
CREATE TABLE Car (
VehicleID INT PRIMARY KEY,
FOREIGN KEY (VehicleID) REFERENCES Vehicle(VehicleID),
EngineType VARCHAR(50)
);
CREATE TABLE Truck (
VehicleID INT PRIMARY KEY,
FOREIGN KEY (VehicleID) REFERENCES Vehicle(VehicleID),
CargoCapacity INT
);
* This structurepreserves the IsA relationshipbetween Vehicle (supertype) and Car/Truck (subtypes).
Why Other Options Are Incorrect:
* Option A (Strong entity) (Incorrect):Strong entitiesdo not rely on a supertype/subtype hierarchy.
* Option C (Associative entity) (Incorrect):Used toresolve many-to-many relationships, not supertype
/subtype relationships.
* Option D (Weak entity) (Incorrect):Weak entitiesdepend on a strong entity, but supertype-subtype relations useinheritance(not dependency).
Thus, the correct answer isIsA relationship, as it describes theinheritance hierarchybetweensupertypes and subtypes.


NEW QUESTION # 47
Which product has an open-source license in addition to having a non-relational system?

  • A. Oracle Database
  • B. MySQL
  • C. MongoDB
  • D. SQL Server

Answer: C

Explanation:
MongoDB is aNoSQL (non-relational) databasethat isopen-sourceand supportsdocument-oriented storage
. It allows for flexible schema design and is optimized for big data applications.
* Option A (Correct):MongoDB is aNoSQL databasewith an open-sourceAGPLlicense, making it both free to use and non-relational.
* Option B (Incorrect):SQL Serveris arelational database(RDBMS) developed by Microsoft and isnot open-source.
* Option C (Incorrect):MySQLisopen-sourcebut is arelational database(RDBMS), not a NoSQL system.
* Option D (Incorrect):Oracle Databaseisrelationalandproprietary(not open-source).


NEW QUESTION # 48
Which term defines a column, or group of columns, that refers to a primary key in a different table?

  • A. Super key
  • B. Foreign key
  • C. Simple key
  • D. Composite key

Answer: B

Explanation:
Aforeign keyis a column (or a set of columns) that establishes arelationship between two tablesby referencing theprimary key of another table.
Example Usage:
sql
CREATE TABLE Departments (
DeptID INT PRIMARY KEY,
DeptName VARCHAR(50)
);
CREATE TABLE Employees (
EmpID INT PRIMARY KEY,
Name VARCHAR(50),
DeptID INT,
FOREIGN KEY (DeptID) REFERENCES Departments(DeptID)
);
* DeptID in Employees is a foreign key, referencing DeptID in Departments.
* Ensuresreferential integrity# DeptID in Employeesmust existin Departments.
Why Other Options Are Incorrect:
* Option A (Super key) (Incorrect):Asuper keyis any set of columns that uniquely identifies a row, but itdoes not reference another table.
* Option B (Simple key) (Incorrect):Asimple keyis asingle-column primary key, not a reference to another table.
* Option C (Composite key) (Incorrect):Acomposite keyconsists ofmultiple columnsbut does not necessarily reference another table.
Thus, the correct answer isForeign key, as it establishes aconnection between two tables.


NEW QUESTION # 49
......

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