Pass Guaranteed Quiz 1z0-071 - Oracle Database SQL Updated New Exam Online

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Oracle Database SQL Sample Questions (Q167-Q172):

NEW QUESTION # 167
Examine these statements:
CREATE TABLE dept (
deptno NUMBER PRIMARY KEY,
diname VARCHAR2(10) ,
mgr NUMBER ,
CONSTRAINT dept_fkey FOREIGN KEY(mgr) REFERENCES emp (empno));
CREATE TABLE emp (
Empno NUMBER PRIMARY KEY,
Ename VARCHAR2 (10) ,
deptno NUMBER,
CONSTRAINT emp_fkey FOREIGN KEY (deptno) REFERENCES dept (deptno) DISABLE); ALTER TABLE emp MODIFY CONSTRAINT emp_fkey ENABLE; Which two are true?

A. All three statements execute successfully in the order shown
B. Both foreign key constraint definitions must be removed from the CREATE TABLE statements, andbe added with ALTER TABLE statements once both tables are created, for the two CREATE TABLEstatements to execute successfully in the order shown.
C. The CREATE TABLE EMP statement must precede the CREATE TABLE DEPT statement for all threestatements to execute successfully.
D. The MGR column in the DEPT table will not be able to contain NULL values.
E. The Deptno column in the emp table will be able to contain nulls values.
F. The DEFT FKEY constraint definition must be removed from the CREATE TABLE DEF statement.and be added with an AITER TABLE statement once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.

Answer: E,F

NEW QUESTION # 168
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.

The PROD_ID column is the foreign key in the SALES tables, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?

A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified columns would be passed to the new table.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the specified columns would be passed to the new table.

Answer: C

NEW QUESTION # 169
Examine these statements which execute successfully:

Both statements display departments ordered by their average salaries.
Which two are true?

A. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.
B. Both statements will display departments with no employees.
C. Only the second statement will display departments with no employees.
D. Only the first statement will display departments with no employees.
E. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
F. Both statements will execute successfully If you add e.avg_sal to the select list.

Answer: C,F

Explanation:
A . Only the second statement will display departments with no employees. This is true because the second statement uses a LEFT JOIN to include all departments from the departments table, even those without matching entries in the employees table. When there are no employees in a department, the AVG(salary) will be NULL, and the department will still be displayed1.
C . Both statements will execute successfully if you add e.avg_sal to the select list. This is correct. Both statements calculate e.avg_sal as an average salary, either through a subquery or a join operation. Adding e.avg_sal to the select list will display the average salary alongside the departments. However, it's important to note that the first statement will not display departments with no employees because it does not use a join that would allow for NULL values from the employees table2.
Reference:
Understanding SQL JOINs - Stack Overflow1.
Oracle Documentation on JOIN Operations2.
Note: The other options are incorrect because:
B . The first statement will not display departments with no employees since it does not use a join that includes departments without matching employee records.
D . As explained, the first statement will not display departments with no employees.
E . There is a typo in the option; it should be E.AVG_SAL. Even if corrected, the first statement alone would not execute successfully because it does not include a join to bring in the avg_sal value.
F . The second statement will display departments with no employees, but the first statement will not, so this option is incorrect.

NEW QUESTION # 170
The CUSTOMERS table has a CUST_CREDT_LIMIT column of data type number.
Which two queries execute successfully?

A. SELECT TO_CHAR(NVL(cust_credit_limit * .15,'Not Available')) FROM customers;
B. SELECT NVL2(cust_credit_limit,TO_CHAR(cust_credit_limit * .15),'NOT Available') FROM customers;
C. SELECT NVL2(cust_credit_limit * .15,'Not Available') FROM customers;
D. True - This query uses NVL2 correctly by checking if cust_credit_limit is not NULL, then applying TO_CHAR to compute 15% of it and converting it to string, or returning 'NOT Available' if it is NULL. The syntax and function usage are correct.
E. SELECT NVL(cust_credit_limit * .15,'Not Available') FROM customers;
F. SLECT NVL(TO_CHAR(cust_credit_limit * .15),'Not available') from customers;

Answer: A,B

Explanation:
A : True - The TO_CHAR function is used correctly here to convert the numeric value to a string, and NVL handles the case where cust_credit_limit might be NULL. The expression inside NVL computes 15% of the credit limit or displays 'Not Available' if the credit limit is NULL. The syntax is correct.
B : False - The NVL2 function requires three parameters: the expression to check for NULL, the value to return if it's not NULL, and the value to return if it is NULL. The given usage lacks the required parameters and syntax.
C : False - The NVL function expects both parameters to be of the same data type. Since the second parameter 'Not Available' is a string, it causes a data type conflict with the numerical result of the first parameter.
D : False - The keyword SELECT is misspelled as SLECT, making the syntax incorrect.

NEW QUESTION # 171
On your Oracle 12c database, you invoked SQL *Loader to load data into the EMPLOYEEStable in the HR schema by issuing the following command:
$> sqlldr hr/hr@pdb table=employees
Which two statements are true regarding the command? (Choose two.)

A. It fails because no SQL *Loader data file location is specified.
B. It fails because no SQL *Loader control file location is specified.
C. It fails if the HR user does not have the CREATE ANY DIRECTORYprivilege.
D. It succeeds with default settings if the EMPLOYEEStable belonging to HR is already defined in the database.

Answer: C,D

Explanation:
Explanation/Reference:

NEW QUESTION # 172
......

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Pass Guaranteed Quiz 1z0-071 - Oracle Database SQL Updated New Exam Online

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Oracle Database SQL Sample Questions (Q167-Q172):

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